Nothing new. That is actually a direct copy of a HP 16074A 4-terminal quasi inductance standard. Even the pictures of the article were copied directly from the HP manual. > 2015-08-20 11.50 UTC+03.00, Dr. David Kirkby (Kirkby Microwave Ltd) > <drkirkby@kirkbymicrowave.co.uk>: > >> If this was April the first, I would be convinced that paper was an April >> Fools Joke! >> >> I can't imagine how you can make high Q (low loss) inductors, by using a >> capacitor and two resistors. It just makes no sense to me, but I will >> read >> the maths later. The mere fact there is resistance makes me think it must >> be lossy, so low Q. Also the equations seems to come out with convenient >> numbers - R in Ohms, C in pF and H in Henries. >> >> But if the paper is real, it is very close to what I want, although it >> still leaves the position of finding stable capacitors. I thought >> inductors >> would be easier than capacitors, but maybe not. >> >> Dave >> _______________________________________________ >> volt-nuts mailing list -- volt-nuts@febo.com >> To unsubscribe, go to >> https://www.febo.com/cgi-bin/mailman/listinfo/volt-nuts >> and follow the instructions there. >> >

Found the HP manual as suggested by Will: it is now clear where the capacitor is connected. On page 1 of the manual changes (page 3 of the PDF file) there is a very clear drawing of the quasi-inductance standard. The "C" port has no guard connections and is used to test the capacitor alone. <https://www.valuetronics.com/Manuals/Keysight-Agilent-HP-16074A.pdf> On Fri, Aug 21, 2015 at 3:51 PM, Will <willvolts@gmail.com> wrote: > Nothing new. That is actually a direct copy of a HP 16074A 4-terminal > quasi inductance standard. Even the pictures of the article were > copied directly from the HP manual. > >> 2015-08-20 11.50 UTC+03.00, Dr. David Kirkby (Kirkby Microwave Ltd) >> <drkirkby@kirkbymicrowave.co.uk>: >> >>> If this was April the first, I would be convinced that paper was an April >>> Fools Joke! >>> >>> I can't imagine how you can make high Q (low loss) inductors, by using a >>> capacitor and two resistors. It just makes no sense to me, but I will >>> read >>> the maths later. The mere fact there is resistance makes me think it must >>> be lossy, so low Q. Also the equations seems to come out with convenient >>> numbers - R in Ohms, C in pF and H in Henries. >>> >>> But if the paper is real, it is very close to what I want, although it >>> still leaves the position of finding stable capacitors. I thought >>> inductors >>> would be easier than capacitors, but maybe not. >>> >>> Dave >>> _______________________________________________ >>> volt-nuts mailing list -- volt-nuts@febo.com >>> To unsubscribe, go to >>> https://www.febo.com/cgi-bin/mailman/listinfo/volt-nuts >>> and follow the instructions there. >>> >> > _______________________________________________ > volt-nuts mailing list -- volt-nuts@febo.com > To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/volt-nuts > and follow the instructions there.

Haha, so it is legit - just a poorly decribed knock-off of the H-P unit. I had never heard of this unit, but it looks like good info to have, to replicate some equivalent reference inductors. Thanks for finding this document. Ed

Haha, so it is legit - just a poorly described knock-off of the H-P unit. I had never heard of this unit, but it looks like good info to have, to replicate some equivalent reference inductors. Thanks for finding this document. Ed

Sorry about the previous double-posting - had email problems. There is another option that occurred to me last night, to get an equivalent inductor from an accurate reference capacitor by using an active circuit gyrator. The problem of course is that the circuit will add errors too, diminishing performance. Also, for four-port use, the circuit would have to be battery-powered, and float within the fixture, adding more parasitics. I could experiment with such a circuit fairly easily since I use my ground-converter for nearly all measurements, so the gyrator would not have to float. All in all though, it still seems that just using a capacitor and resulting negative inductance readout is the simplest and most accurate approach. Ed