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Discussion of precise time and frequency measurement

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ADEV noise floor vs counter gate time

J
jpbridge@aol.com
Mon, Mar 23, 2015 9:12 PM

Hi Bill,

I'm travelling at the moment, but I had another go just now and it has stopped wiping my details when I press the save button so hopefully that means it is fixed.

I must just have been unlucky and picked a glitchy day (this was at the end of last week).

Though, now that I've downloaded NI-VISA and got that working I probably don't need to download tek-VISA.

Best Regards,

James

-----Original Message-----
From: Bill Byrom time@radio.sent.com
To: time-nuts time-nuts@febo.com
Sent: Sun, 22 Mar 2015 20:28
Subject: Re: [time-nuts] ADEV noise floor vs counter gate time

Was the website problem this past week? The main Tek US website was
acting up
for a while one day this week, but seems to be fine now. I
have no insights on
European access.

--
Bill Byrom N5BB

On Sun, Mar 22, 2015, at 07:10 AM,
James via time-nuts wrote:

Hi Bill,

Thanks for the pointers.

I

should say that my results reported so far have been with my older TTi

TF930

reciprocal counter, not with my FCA3100 which I have only just got

(it

arrived a few days ago) and I'm in the process of writing software to

talk to

it via the USB.

I did discover the website, in fact I'd downloaded the

manual before

buying the counter, and it is fortunate I did because the

website for me

didn't work - I'm currently talking to Tek support about

it.

The problem is that to download software you must have your

details

registered. Every time I register my details and press the "save"

button

the site wipes all my details and returns to a blank form. When I try

to

down load the software it then stops me and tells me to update my

details. I update my details and it blanks the form and so on... slightly

frustrating. I've tried both Firefox and IE.

The other thing is that the

manuals don't show on the European site (I'm

in the UK), you click on them

but the download screen just shows a blank

line. I got round this by going to

the international site and just

closing the screen asking me for my area

rather than responding to it - I

had to do this several times.

I have

now downloaded NI-VISA and have managed to do a bit of talking to

the

instrument over USB though I've not yet had time to do this properly.

So

in summary - I'm pleased with my counter but the Tek website for

Europe at

least has some serious bugs which hopefully will be fixed soon.

The Tek

support person I spoke to on the phone was helpful but she wasn't

in a

position to fix the web site issues directly so has forwarded my

case to Tek

IT.

I intend repeating my TTi TF930 experiment with my FCA3100 when I've

got

everything working ok and am looking forward to seeing the results.

James

-----Original Message-----
From:

To: time-nuts time-nuts@febo.com
Sent:

Sun, 22 Mar 2015 2:27

Subject: Re: [time-nuts] ADEV noise floor vs counter

gate time

Hi, James. I'm a Tektronix RF Application Engineer in

Dallas and thought

I
would throw in a few points about your FCA3100 (if

you haven't read up

on these
already):

All Tektronix manuals and

technical reference documents can

be
downloaded for no charge on our

website (http://www.tek.com), but

some
items may require you to register

and sign in. The detailed

specification
and performance verification

document (document number

077-0495-01) has many
details about the

specifications, and is

at:

All
downloadable files for this product can be found in the list

at:

used

counter, be sure you check the firmware version and update it if

needed.

If your exact model is "FCA3000", you have a 300 MHz counter with

100

ps
single-shot resolution. This counter has reciprocal counter

features

(based
on a 10 ns main counter time resolution), but also uses

100 ps

RMS jitter
interpolation to determine edge location with an

additional

X100 resolution.
When the initial edge of the signal you are

measuring

is detected, the
interpolater resolves this edge with 100 ps

resolution

relative to the internal
10 ns clock. After the desired

measurement

interval, the final edge is also
resolved with 100 ps

resolution, and

the number of signal edges and
interpolated

intitial-to-final time are

used to determine the frequency (for
example).

The analog interpolation

circuit uses a constant current charging a

capacitor with a sampler and

A/D converter. Counting a 100 MHz signal,

this

provides 12 digits of
resolution per second of measurement

interval.

--
Bill Byrom N5BB

On Wed, Mar 18, 2015, at

05:49 PM, James

via time-nuts wrote:

Hi Dave,

Thanks for

another detailed

response.

I've now programmed a version of my code

that attempts to

recover the

raw data by trying different counts up and

down from the nominal

and

finding the one with the smallest rounding

error.

One problem is I

need to restrain the amount it goes up or

down

otherwise it finds erroneously

small or large numbers of cycles

(+/- 2

is believable, more than that

isn't).

As an experiment

I then changed the data to match the "raw data".

This

doesn't change the

shape of the curve but it lowers it so it starts

below 10^-15! This is

suspiciously good so I think I'm smoothing out

changes

that are really

there.

Now that my new fca3100 has arrived I'm hoping to

find time

to get

measurements with it which should be proper time-stamped

ones and

much

more accurate - then I can compare the two.

To answer

your question on ADEV aggregating values, and speaking as a

total newbee

myself, the approach to different tau sizes is to

aggregate all

measurements

within a bin of size tau and average the

frequencies (or

average the time

differences and invert - for small

variations it makes

very little difference

as (1+delta)^-1 is 1-delta

ignoring delta*delta

terms). Then each term in the

Alan Variaton

summation is the square of

the difference between the

average

frequency in adjacent bins.

So with 1 second values at a tau of

100 secs, 100 values in each cell

are averaged whilst the 100 sec gate value

results just have a single

value for each bin. But given that the counter

itself should be

averaging there should be good agreement between the two -

hence my

puzzlement.

The fca3100 calculates ADEV directly so I'll have

a

check on my code.

James

-----Original

Message----- From: Dave Martindale

Discussion of precise time and frequency

measurement

time-nuts@febo.com Sent: Wed, 18 Mar 2015 15:22 Subject:

Re:

[time-nuts] ADEV noise floor vs counter gate time

The

counter always has a 1 count uncertainty in the timebase

measurement,

which

is a 2e-8 error with a 1 second gate time. If the

value being

displayed

starts with the digit 9, and 8 digits are

displayed, then that

translates to

+- 2 counts in the last place. But

the measurements are

synchronized to the

input signal, so it always

measures an integer

number of input cycles, and

there should be no

comparable uncertainty in

the input (other than some noise

in deciding

exactly when the edge

crosses the input threshold, which should

be

tiny compared to the 20 ns

timebase period).

But that's

comparing the counter

reading to the real world. My table

was comparing the

displayed output

to the likely raw measurements, and

it seems to show that

the counter's

internal math is being performed

to the full 10 digits of

precision in

the USB data, even when the gate

time supports only 8 bits of

accuracy.

That's good news because it

allows you to know when you have

correctly

guessed the input counts.

When trying to calculate

the

raw data from the reading, you do need to

try an input count of 91

in

addition to 90 and 92. 91 did show up in

the small sample of

period-mode

measurements, even if it did not

appear in any of the

frequency-mode

measurements.

I don't think the

counter is doing "averaging", in

the sense of making

multiple

independent short-period measurements and then

averaging them

for higher

precision. Instead, it is just making one long

continuous

measurement,

sampling the signal periodically, and then

actually

calculating

frequency or period from two measurements separated by

an

appropriate

time. For a simplified example:

Suppose the

counter

generates a time stamp approximately every 1

second (always aligned

with

the input signal active edge) and then

stores the two pieces of raw data

(the current input cycle counter and

the current timebase counter) in a

small

memory buffer. The counters

are never reset; they just need to be

large

enough to never overflow

twice within the longest input period

allowed (1000

s for the TF930).

To display a frequency or period based

on a 1 s gate time,

the counter

simply subtracts two successive data

records to get delta-input

and

delta-timebase counts, then does its

calculations based on those

deltas. To display a 10 second gate time

measurement, the counter

looks back

through its memory to find a time

stamp about 10 seconds

earlier than the

most recent measurement (with

high input frequency,

that will generally be 10

measurements ago, but

when measuring a

signal with a 0.2 Hz frequency it's

only 2 measurements

ago). For a

100 second gate time measurement, the count

er needs to find

a saved

time stamp that is about 100 seconds ago. Once it

has found

the

correct data record, it calculates the difference in input

and

timebase counts between that one previous data record and the most

recent, and then calculates the displayed value from it.

One
second later, the counter can calculate a new 100 s measurement,

using the

new data point just captured and a different stored data

point

100 seconds

ago. But 99 of the 100 seconds in the new gate

period are

shared with the old

gate period, so the displayed value is

not likely to

change very much simply

because 99% of the observation

period is

shared.

Thus, every

displayed value is calculated

from only 2 time-stamped

measurements. The

longer gate time places those

measurements further

apart, reducing the

uncertainty due to the +- 1

clock of the timebase.

Because the counters run

continuously without

resetting, no clock

edges are lost and a 100 s gate time

measurement has

only 20 ns

uncertainty in the whole 100 s period. Also, any

wander in

the input

frequency between those two measurements is invisible if

it

cancels

out over the gate time. So there is "averaging" in the sense

that

the

counter display always reflects what is happening on the scale

of the

gate time, but it's not computing and then averaging multiple

numbers.

I have not tried doing my own ADEV

calculations, so I

can't say what

it is about the shorter gate periods

that make the oscillator

appear

noisier than it really is. How does the

ADEV calculation aggregate

a

stream of short-time calculations into

measurements for large tau

values? My intuition is this: If you just

take readings from the

counter with

a 1 s gate time, each reading has a

2e-8 uncertainty. If

you average a bunch

of these readings, and the

errors are independent,

the accuracy should

improve by a factor of

sqrt(N). But if you unwrap

each reading into an

integer number of input

and timebase cycles, you

essentially have a series of

phase samples that

can be added or

subtracted without increasing the absolute

uncertainty.

So when you

combine 100 1 second measurements, you get a

relative

accuracy that is

100 times better, not the sqrt(100) you'd get from

averaging.

  • Dave

On

Wed, Mar 18, 2015 at

6:33 AM, jpbridge@aol.com wrote:

Hi Dave,

Interesting analysis.

The accuracy stated in the manual is ...+ 2

counts and though this relates to

the 50MHz clock, perhaps they use a

similar algorithm for the input

frequency.

I completed the 0.3

second measurements and the curve is

similar to 1

second but higher up

(i.e. as you'd expect by extrapolation from

the

behaviour of the other

curves).

My ADEV calculation is based on the

average frequency in

each bin, the

varying size of the bin should be

insignificant as long as

it is not

affecting the average value within the

bin. If the average

frequency

shifts by delta_F in one bin time step and the

first bin is

delta_T

short (as a fraction of one bin time step) then the

first

frequency

will be delta_T*delta_F low and the second bin perhaps that

much high

but the key point is that it is the product of the two deltas

so

it

won't materially affect the accuracy of the calculation. At least

I

think that is correct.

Taking the worst possible case where

the delta in

bin size always went

the wrong way so every term in the

Alan Variance sum was

multiplied by

(1+2delta)^2 then the final Alan

deviation might be (1 + 2

delta) too

big but as delta is of the order of

10E-8 or less this wouldn't

even

register on the graphs.

What

I might try doing is programming your

approach into the code to

try and

get at the raw data - I only need to try

88,90 and 92 as

possible counts

  • though to be sure I'll try mean frequency

+- 5 say

and then try and

get the 50MHz clock values out as integers. What

I

might also do is then

do a least squares fit (linear regression) to

get

the frequency over

each bin and use the slope (this perhaps is

what the

counter does

internally - I don't know).

I'd like to get to the bottom of

this

if only to understand my

counter better.

James

-----Original

Message-----

From: Dave Martindale

To: jpbridge <

Sent: Wed, 18 Mar 2015

1:26 Subject: Re: [time-nuts] ADEV noise floor

vs

counter gate

time

I believe I see the pattern. As you

figured out, you wouldn't

expect a

single period to be a multiple of 20

ns; you expect the length of

(about) 90 periods to be an integer

multiple of 50 ns, since that's

what the

counter actually measures.

Further, the measuring time isn't

exactly 1

second, it is an integer

number of periods of the input

frequency that makes

up at least 1

second. If the counting logic was

all hardware, you would

expect to

capture either 90 or 91 cycles of

the input, depending on whether

the

input frequency was slightly below

or above 90 Hz respectively.

I

built this table of your frequency data in Excel. Math is 64-bit

floating

point, equivalent to about 16 decimal digits, so plenty

accurate enough to

simulate this counter:

Reading Input Count TB

Count Rounded Frequency

Interval 90.00006359 92

51111074.998 51111075

90.00006359 1.022221500

90.00007591 92

51111068.002 51111068 90.00007591

1.022221360 89.99999640

90

50000002.000 50000002 89.99999640 1.000000040

89.99998740 90

50000007.000 50000007 89.99998740 1.000000140 90.00006007

92

51111076.997

51111077 90.00006007 1.022221540 89.99996040 90

50000022.000 50000022

89.99996040 1.000000440 90.00008648 92

51111061.999 51111062 90.00008648

1.022221240 90.00008472 92

51111062.999 51111063 90.00008472 1.022221260

90.00011465 92

51111046.001 51111046 90.00011465 1.022220920 90.00014459

92

51111028.998 51111029 90.00014459 1.022220580

The first column is

your data. The second column is a guess about how

many input cycles were

captured. The third column is the number of

timebase cycles that have

elapsed

since the previous reading, based on

the first two columns. I

hand-tweaked

the numbers in the second column

until the number in the

third column was

within 0.003 of an integer.

The fact that I was always

able to do this tells

me that my guess is

probably correct, and the

small residual (which is a few

parts in

1e-10) is due to the counter

rounding the results to 10 digits.

The

4th column is the result of

rounding the previous column to the

nearest integer. This is what I

believe is the actual number of counts

the

counter saw. The 5th column

is a fresh calculation of frequency,

based on the

integer number of

input cycles in column 2 and the

integer number of timebase

cycles in

column 4. When the result is

rounded to 10 digits, you can see it

matches the 10 digits that the

counter provided back in column 1.

Oddly, the counter never captured 91 input cycles. If the input

frequency was

a little higher than 90 Hz, it always measured at 92

cycles, even though 91

cycles was well more than 1 s since the

previous

reading. I guess the

microprocessor running the counter only

checks

periodically (e.g. every 20

ms) to see if the gate time has

elapsed, and

then latches the counts on the

next active edge of the

input signal.

So, I claim that with this small

sample, at least, we recovered the

exact number of 20 ns periods between
samples, and the number of

integer input cycles as well. Also notice the 6th

column. This is the

actual sample interval, based on the number of elapsed

timebase

counts.

Note that the sample period is not exactly 1 second,

nor

is it even

close to a constant value, since some measurements are of

90 cycles

while others are of 92 cycles. Does your ADEV calculation

algorithm

take

into account the variable spacing of the input samples

in time? If it

assumes they are regularly spaced (i.e. every 90

cycles) it may get

confused

by this variable-spacing data.

Now here is almost the same

process applied

to your period data:

Reading Input Count TB Count

Rounded Period Interval

0.01111107736 91

50555401.988 50555402

0.01111107736 1.011108040

0.01111110130 92

51111065.980 51111066

0.01111110130 1.022221320

0.01111110769 91

50555539.990 50555540

0.01111110769 1.011110800

0.01111110435 92

51111080.010 51111080

0.01111110435 1.022221600

0.01111110593 91

50555531.982 50555532

0.01111110593 1.011110640

0.01111110022 90

49999950.990 49999951

0.01111110022 0.999999020

0.01111114000 90

50000130.000 50000130

0.01111114000 1.000002600

0.01111110000 90

49999950.000 49999950

0.01111110000 0.999999000

0.01111110370 92

51111077.020 51111077

0.01111110370 1.022221540

Again,

column 2 was hand-adjusted for

each row to keep the third

column close to an

integer. The residual

errors here are larger, since

the maximum rounding

error of 0.5 in the

last place is a larger change

relative to a 10-digit

value of 11111111

than it is to a value of

90000000, but all are still within

0.02 of

being an integer. This

time, the counter grabbed measurements after

90,

91, or 92 cycles.

Again, after rounding the timebase count to an integer

and calculating

a 10-digit period for display, the result always matched

what

the

counter output. Again, I think we know with high probability

just how

many input and timebase cycles were counted for each

measurement.

I

adjusted column 2 by eye, while looking at the

results of column 3,

but that

process could be automated pretty easily

(just not in Excel).

As I tried 90,

91, and 92 in sequence, there was

always just one of

those which gave a small

residual error.

So

I think your TF930 is making measurements and

accurately converting

them

to frequency or period, with a +- 20 ns

uncertainty for each

measurement. Since it is a time-stamping counter, the

uncertainty in a

10 s or 100 s or 1000 s measurement time (assembled by

external

software) is still only 20 ns. That's great, but to actually get

that

accuracy over a long measurement time, you will need to determine and

add up the actual number of input counts and timebase counts. And you

will

have to understand that the counter does not make measurements at

constant or

near-constant intervals (e.g. every 90 cycles of input,

without exception).

It gives you measurements whenever it gets around

to

measuring them.

Too bad there doesn't seem to be a way to get it to

return the raw

observed

data (input cycle count, timebase cycle count)

instead of

the frequency or

period derived from them. That would make it

trivial

to string together a

bunch of 1s measurements into arbitrarily

long

gate times.

Dave

On 17/03/2015 05:57,

Hi

Dave,

Thank you for your

detailed response.

I use the E? command

because it returns results

at the gate time

intervals rather than at the LCD

update rate (as you

point out). I

think that this is working correctly

because I get very

different

file sizes.

The numbers are returned as

strings of

10 digits - here are some for 1

second gate:

90.00006359e+0Hz

90.00007591e+0Hz
89.99999640e+0Hz

89.99998740e+0Hz

90.00006007e+0Hz

89.99996040e+0Hz

90.00008648e+0Hz

90.00008472e+0Hz

90.00011465e+0Hz

90.00014459e+0Hz

I generally use the frequency mode

but I also

tried time period and

found I got the same curve in essence, which

was

comforting in a way

but showed it wasn't rounding in converting to

frequency.

The numbers above, on my calculator at least don't

exactly

match

counts of 20 nanosecs.

Here are some time period

results:

11.11107736e-3s

11.11110130e-3s

11.11110769e-3s

11.11110435e-3s

11.11110593e-3s

11.11110022e-3s

11.11114000e-3s
11.11110000e-3s

11.11110370e-3s

Again they don't seem to be integer values of 20

nanosec

exactly,

though quite close. For example

11.11107736E-3/20E-9 =

555,553.868 555,554 x 20E-9 = 11.11108E-3

But I guess what it returns is

the ratio of counts within the gate. So

11.11107736E-3 period will occur 90

times in a second (as it is

slightly short) and so I should take the

ratio:

90 x

11.11107736E-3/20e-9 = 49,999,848.12

so still not quite

an integer

but if I assume the count (of 50MHz

periods) was 49,999,848 and

calculate one 90 th of it I get:

49,999,848 x 20E-9/90 =

1.1111077333333

Still not exact agreement. I note that .12 is very

close

to .125 or

1/8 but I don't know if that is significant. It is

probable that

it

rounds the ratio in binary and then converts to decimal

to print

out.

I've tried assuming 89 periods and 91 periods but

still don't get

exact integer ratios.

Anyway, as I get good

agreement between period and

frequency

measurements at 1 sec, I don't

think that it is a rounding

issue.

I do think it is a quantization

issue down to the +/- 20

nanosecs/gate

time but I can't quite work it

out.

I'm currently doing a

run at 0.3 secs gate time and I'll see

what sort

of curve that

produces.

Tomorrow I should receive my

new Tek counter (I went for the

fca3100

in the end as I got a very good

discount on an ex demo unit) and

that should give something to compare

(once I've worked out how to

program

it).

James

-----Original Message----- From: Dave

Martindale

Discussion

of precise time and frequency measurement

Tue, 17 Mar 2015 0:27 Subject: Re:

[time-nuts] ADEV noise floor vs

counter gate time

How is the counter configured? Are

you reading

period or frequency?

Are you in "E?" (Every Result) mode, or

"C?" (Continuous

Result) mode?

The former should give you continuous but

independent

measurements,

while the latter gives heavily overlapped

measurements. (For

example,

with a 100 second gate time, you get one E

output every 100

seconds,

which covers a different 100-second period

than the previous

measurement. In C mode, you get one output every 2

seconds, each of

which is

an estimate from 100 seconds of measurement,

but 98 seconds

of that data was

also part of the previous output and

only 2 seconds

of new data is

included).

What

does the data returned by the counter actually

look like? The

manual

implies that you always get 10 digits worth of result

(not

including the

exponent) regardless of gate time, but are the values

rounded for

display in 7, 8, or 9 digits at the shorter gate times, or

are

they a

full 10 digits always? Given any particular value of

frequency or

period

you get, you should be able to reverse-calculate

the number of whole

cycles of the input signal that the counter used

as a gate time, and the

number of cycles of 50 MHz timebase that were

counted in that period.

Since

the counter doesn't have interpolators,

both of these values

should be

integers, and so the possible output

values are a small subset

of all

possible 10-digit values for the

shorter gate times.

For example,

if the difference frequency is exactly 90 Hz, the

period

between two "1

second" measurements will be exactly 1 second, and

the

counter will record 90

cycles of input and 5e7 cycles of

timebase,

exactly. In frequency mode, the

output should be 90.0 Hz

exactly, and

in period mode the output should be

11.11111111 ms. Now

suppose that

the difference frequency is just a hair

slow, enough that

90 cycles of

input spans 50,000,001 counts of the timebase.

The reported

frequency

should be 89.99999820 Hz and the reported period

should be

11.11111133

ms. With a 1 s gate time, no values between those are

possible unless

the values are being rounded (or there is an error in

the

calculation,

which is always possible). Looked at another way,

the

smallest

possible change in the reported period is one timebase

clock (20

ns)

divided by the number of input cycles in one gate time (90

for 1

s).

If the counter is rounding, you may be

able to unambiguously

figure

out what the actual inputs (cycles of input

and cycles of timebase)

to

the calculation were, and use that instead of

the rounded value in

your

calculations. Rounding may round up or down,

but if the two

oscillators are

stable enough the direction can be

predominantly "up"

or "down" for long

periods of time, adding a bias to

the actual

frequency or period you're

measuring. (I don't know what

effect this

bias would have on

ADEV).

  • Dave

On Mon, Mar 16, 2015 at 10:15 AM,

James via

time-nuts

time-nuts@febo.com wrote:

Hi All,

I'm in

the process of getting a better counter, but at present I'm

using my TTi

TF930 counter.

For those who don't know it, it is a reciprocal

counter

which should

be continuous, it counts periods in terms of its

internal 50MHz

clock

which I've locked to an external 10MHz

reference.

There are 4

gate times available, 0.3 secs, 1 sec, 10

secs and

100 secs.

These

correspond to 7, 8, 9 and 10

digits.

I've been experimenting with using a

single mixer (mini

circuits ZAD+)

along with a 1MHz low pass filter and

appropriate

attenuators to

measure Alan Deviation (using my own

software).

My set up is a 10MHz reference source (MV89A which I've

approximately

set using a 10kHz GPS signal).

The reference is used as

the

external reference for an Agilent 33522A

arbitrary waveform

generator.

The 33522A generates an 9.999910 MHz (10MHz - 90Hz) sine

wave

at

300mVpp to the mixer and the mixer is also fed by the 10MHz

reference

output of the 33522A via an attenuator to get it to

roughly

the same

level.

The second output of the 33522A generates a 10MHz

square wave as

a

reference for the counter (the counter requires quite a

high reference

signal and the reference out of the 33522A is too low a

voltage to be

used

directly).

I initially ran this with a gate

of 1 second and the

LOG10(ADEV) curve

drops linearly vs LOG10(tau) but

then curves back up again.

(I tried

many variants such as using period

rather than frequency and so

on.)

But when I set the gate time to

10 seconds or 100 seconds then I

get

both lower curves and ones that no

longer curve upwards.

The

attached pdf shows the three curves on

the same graph.

What puzzles me is

that the counter at longer gates

is only averaging

to get more digits so the

difference must come down to

quantization in

terms of the number of digits

that are passed to the

computer over the

USB/RS232 link.

I find it

rather

puzzling.

James


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Hi Bill, I'm travelling at the moment, but I had another go just now and it has stopped wiping my details when I press the save button so hopefully that means it is fixed. I must just have been unlucky and picked a glitchy day (this was at the end of last week). Though, now that I've downloaded NI-VISA and got that working I probably don't need to download tek-VISA. Best Regards, James -----Original Message----- From: Bill Byrom <time@radio.sent.com> To: time-nuts <time-nuts@febo.com> Sent: Sun, 22 Mar 2015 20:28 Subject: Re: [time-nuts] ADEV noise floor vs counter gate time Was the website problem this past week? The main Tek US website was acting up for a while one day this week, but seems to be fine now. I have no insights on European access. -- Bill Byrom N5BB On Sun, Mar 22, 2015, at 07:10 AM, James via time-nuts wrote: > Hi Bill, > > Thanks for the pointers. > > I should say that my results reported so far have been with my older TTi > TF930 reciprocal counter, not with my FCA3100 which I have only just got > (it arrived a few days ago) and I'm in the process of writing software to > talk to it via the USB. > > I did discover the website, in fact I'd downloaded the manual before > buying the counter, and it is fortunate I did because the website for me > didn't work - I'm currently talking to Tek support about it. > > The problem is that to download software you must have your details > registered. Every time I register my details and press the "save" button > the site wipes all my details and returns to a blank form. When I try to > down load the software it then stops me and tells me to update my > details. I update my details and it blanks the form and so on... slightly > frustrating. I've tried both Firefox and IE. > > The other thing is that the manuals don't show on the European site (I'm > in the UK), you click on them but the download screen just shows a blank > line. I got round this by going to the international site and just > closing the screen asking me for my area rather than responding to it - I > had to do this several times. > > I have now downloaded NI-VISA and have managed to do a bit of talking to > the instrument over USB though I've not yet had time to do this properly. > > So in summary - I'm pleased with my counter but the Tek website for > Europe at least has some serious bugs which hopefully will be fixed soon. > The Tek support person I spoke to on the phone was helpful but she wasn't > in a position to fix the web site issues directly so has forwarded my > case to Tek IT. > > I intend repeating my TTi TF930 experiment with my FCA3100 when I've got > everything working ok and am looking forward to seeing the results. > > James > > > > > > > > -----Original Message----- > From: Bill Byrom <time@radio.sent.com> > To: time-nuts <time-nuts@febo.com> > Sent: Sun, 22 Mar 2015 2:27 > Subject: Re: [time-nuts] ADEV noise floor vs counter gate time > > > Hi, James. I'm a Tektronix RF Application Engineer in Dallas and thought > I > would throw in a few points about your FCA3100 (if you haven't read up > on these > already): > > All Tektronix manuals and technical reference documents can > be > downloaded for no charge on our website (http://www.tek.com), but > some > items may require you to register and sign in. The detailed > specification > and performance verification document (document number > 077-0495-01) has many > details about the specifications, and is > at: > http://www.tek.com/frequency-counter-supplies/mca3027-manual/fca3000-and-fca3100-series-mca3000-series > > All > downloadable files for this product can be found in the list > at: > http://www.tek.com/search/apachesolr_search/fca3000 If you have a > used > counter, be sure you check the firmware version and update it if > needed. > > If your exact model is "FCA3000", you have a 300 MHz counter with 100 > ps > single-shot resolution. This counter has reciprocal counter features > (based > on a 10 ns main counter time resolution), but also uses 100 ps > RMS jitter > interpolation to determine edge location with an additional > X100 resolution. > When the initial edge of the signal you are measuring > is detected, the > interpolater resolves this edge with 100 ps resolution > relative to the internal > 10 ns clock. After the desired measurement > interval, the final edge is also > resolved with 100 ps resolution, and > the number of signal edges and > interpolated intitial-to-final time are > used to determine the frequency (for > example). The analog interpolation > circuit uses a constant current charging a > capacitor with a sampler and > A/D converter. Counting a 100 MHz signal, this > provides 12 digits of > resolution per second of measurement > interval. > > -- > Bill Byrom N5BB > > > > On Wed, Mar 18, 2015, at 05:49 PM, James > via time-nuts wrote: > > Hi Dave, > > > > Thanks for another detailed > response. > > > > I've now programmed a version of my code that attempts to > recover the > > raw data by trying different counts up and down from the nominal > and > > finding the one with the smallest rounding error. > > > > One problem is I > need to restrain the amount it goes up or down > > otherwise it finds erroneously > small or large numbers of cycles (+/- 2 > > is believable, more than that > isn't). > > > > As an experiment I then changed the data to match the "raw data". > This > > doesn't change the shape of the curve but it lowers it so it starts > > > below 10^-15! This is suspiciously good so I think I'm smoothing out > > changes > that are really there. > > > > Now that my new fca3100 has arrived I'm hoping to > find time to get > > measurements with it which should be proper time-stamped > ones and much > > more accurate - then I can compare the two. > > > > To answer > your question on ADEV aggregating values, and speaking as a > > total newbee > myself, the approach to different tau sizes is to > > aggregate all measurements > within a bin of size tau and average the > > frequencies (or average the time > differences and invert - for small > > variations it makes very little difference > as (1+delta)^-1 is 1-delta > > ignoring delta*delta terms). Then each term in the > Alan Variaton > > summation is the square of the difference between the > average > > frequency in adjacent bins. > > > > So with 1 second values at a tau of > 100 secs, 100 values in each cell > > are averaged whilst the 100 sec gate value > results just have a single > > value for each bin. But given that the counter > itself should be > > averaging there should be good agreement between the two - > hence my > > puzzlement. > > > > The fca3100 calculates ADEV directly so I'll have > a check on my code. > > > > James > > > > > > > > > > > > > > > > -----Original > Message----- From: Dave Martindale > > <dave.martindale@gmail.com> To: jpbridge > <jpbridge@aol.com> > > CC: Discussion of precise time and frequency > measurement > > <time-nuts@febo.com> Sent: Wed, 18 Mar 2015 15:22 Subject: > Re: > > [time-nuts] ADEV noise floor vs counter gate time > > > > > > > > The > counter always has a 1 count uncertainty in the timebase > > measurement, which > is a 2e-8 error with a 1 second gate time. If the > > value being displayed > starts with the digit 9, and 8 digits are > > displayed, then that translates to > +- 2 counts in the last place. But > > the measurements are synchronized to the > input signal, so it always > > measures an integer number of input cycles, and > there should be no > > comparable uncertainty in the input (other than some noise > in deciding > > exactly when the edge crosses the input threshold, which should > be > > tiny compared to the 20 ns timebase period). > > > > > > > > But that's > comparing the counter reading to the real world. My table > > was comparing the > displayed output to the likely raw measurements, and > > it seems to show that > the counter's internal math is being performed > > to the full 10 digits of > precision in the USB data, even when the gate > > time supports only 8 bits of > accuracy. That's good news because it > > allows you to know when you have > correctly guessed the input counts. > > > > > > > > > > When trying to calculate the > raw data from the reading, you do need to > > try an input count of 91 in > addition to 90 and 92. 91 did show up in > > the small sample of period-mode > measurements, even if it did not > > appear in any of the frequency-mode > measurements. > > > > > > > > > > I don't think the counter is doing "averaging", in > the sense of making > > multiple independent short-period measurements and then > averaging them > > for higher precision. Instead, it is just making one long > continuous > > measurement, sampling the signal periodically, and then > actually > > calculating frequency or period from two measurements separated by > an > > appropriate time. For a simplified example: > > > > > > > > > > Suppose the > counter generates a time stamp approximately every 1 > > second (always aligned > with the input signal active edge) and then > > stores the two pieces of raw data > (the current input cycle counter and > > the current timebase counter) in a small > memory buffer. The counters > > are never reset; they just need to be large > enough to never overflow > > twice within the longest input period allowed (1000 > s for the TF930). > > To display a frequency or period based on a 1 s gate time, > the counter > > simply subtracts two successive data records to get delta-input > and > > delta-timebase counts, then does its calculations based on those > > > deltas. To display a 10 second gate time measurement, the counter > > looks back > through its memory to find a time stamp about 10 seconds > > earlier than the > most recent measurement (with high input frequency, > > that will generally be 10 > measurements ago, but when measuring a > > signal with a 0.2 Hz frequency it's > only 2 measurements ago). For a > > 100 second gate time measurement, the count > er needs to find a saved > > time stamp that is about 100 seconds ago. Once it > has found the > > correct data record, it calculates the difference in input > and > > timebase counts between that one previous data record and the most > > > recent, and then calculates the displayed value from it. > > > > > > > > > > One > second later, the counter can calculate a new 100 s measurement, > > using the > new data point just captured and a different stored data > > point 100 seconds > ago. But 99 of the 100 seconds in the new gate > > period are shared with the old > gate period, so the displayed value is > > not likely to change very much simply > because 99% of the observation > > period is shared. > > > > > > > > > > Thus, every > displayed value is calculated from only 2 time-stamped > > measurements. The > longer gate time places those measurements further > > apart, reducing the > uncertainty due to the +- 1 clock of the timebase. > > Because the counters run > continuously without resetting, no clock > > edges are lost and a 100 s gate time > measurement has only 20 ns > > uncertainty in the whole 100 s period. Also, any > wander in the input > > frequency between those two measurements is invisible if > it cancels > > out over the gate time. So there is "averaging" in the sense that > the > > counter display always reflects what is happening on the scale of the > > > gate time, but it's not computing and then averaging multiple > numbers. > > > > > > > > > > I have not tried doing my own ADEV calculations, so I > can't say what > > it is about the shorter gate periods that make the oscillator > appear > > noisier than it really is. How does the ADEV calculation aggregate > a > > stream of short-time calculations into measurements for large tau > > > values? My intuition is this: If you just take readings from the > > counter with > a 1 s gate time, each reading has a 2e-8 uncertainty. If > > you average a bunch > of these readings, and the errors are independent, > > the accuracy should > improve by a factor of sqrt(N). But if you unwrap > > each reading into an > integer number of input and timebase cycles, you > > essentially have a series of > phase samples that can be added or > > subtracted without increasing the absolute > uncertainty. So when you > > combine 100 1 second measurements, you get a > relative accuracy that is > > 100 times better, not the sqrt(100) you'd get from > averaging. > > > > > > > > > > - Dave > > > > > > > > > > > > > > On Wed, Mar 18, 2015 at > 6:33 AM, <jpbridge@aol.com> wrote: > > > > Hi Dave, > > > > Interesting analysis. > The accuracy stated in the manual is ...+ 2 > > counts and though this relates to > the 50MHz clock, perhaps they use a > > similar algorithm for the input > frequency. > > > > I completed the 0.3 second measurements and the curve is > similar to 1 > > second but higher up (i.e. as you'd expect by extrapolation from > the > > behaviour of the other curves). > > > > My ADEV calculation is based on the > average frequency in each bin, the > > varying size of the bin should be > insignificant as long as it is not > > affecting the average value within the > bin. If the average frequency > > shifts by delta_F in one bin time step and the > first bin is delta_T > > short (as a fraction of one bin time step) then the > first frequency > > will be delta_T*delta_F low and the second bin perhaps that > much high > > but the key point is that it is the product of the two deltas so > it > > won't materially affect the accuracy of the calculation. At least I > > > think that is correct. > > > > Taking the worst possible case where the delta in > bin size always went > > the wrong way so every term in the Alan Variance sum was > multiplied by > > (1+2delta)^2 then the final Alan deviation might be (1 + 2 > delta) too > > big but as delta is of the order of 10E-8 or less this wouldn't > even > > register on the graphs. > > > > What I might try doing is programming your > approach into the code to > > try and get at the raw data - I only need to try > 88,90 and 92 as > > possible counts - though to be sure I'll try mean frequency > +- 5 say > > and then try and get the 50MHz clock values out as integers. What > I > > might also do is then do a least squares fit (linear regression) to > > get > the frequency over each bin and use the slope (this perhaps is > > what the > counter does internally - I don't know). > > > > I'd like to get to the bottom of > this if only to understand my > > counter better. > > > > > James > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > -----Original Message----- > From: Dave Martindale > > <dave.martindale@gmail.com> > > > > > > To: jpbridge < > jpbridge@aol.com>; time-nuts < time-nuts@febo.com> > > Sent: Wed, 18 Mar 2015 > 1:26 Subject: Re: [time-nuts] ADEV noise floor > > vs counter gate > time > > > > > > > > I believe I see the pattern. As you figured out, you wouldn't > expect a > > single period to be a multiple of 20 ns; you expect the length of > > > (about) 90 periods to be an integer multiple of 50 ns, since that's > > what the > counter actually measures. Further, the measuring time isn't > > exactly 1 > second, it is an integer number of periods of the input > > frequency that makes > up at least 1 second. If the counting logic was > > all hardware, you would > expect to capture either 90 or 91 cycles of > > the input, depending on whether > the input frequency was slightly below > > or above 90 Hz respectively. > > > > I > built this table of your frequency data in Excel. Math is 64-bit > > floating > point, equivalent to about 16 decimal digits, so plenty > > accurate enough to > simulate this counter: > > > > Reading Input Count TB Count Rounded Frequency > Interval 90.00006359 92 > > 51111074.998 51111075 90.00006359 1.022221500 > 90.00007591 92 > > 51111068.002 51111068 90.00007591 1.022221360 89.99999640 > 90 > > 50000002.000 50000002 89.99999640 1.000000040 89.99998740 90 > > > 50000007.000 50000007 89.99998740 1.000000140 90.00006007 92 > > 51111076.997 > 51111077 90.00006007 1.022221540 89.99996040 90 > > 50000022.000 50000022 > 89.99996040 1.000000440 90.00008648 92 > > 51111061.999 51111062 90.00008648 > 1.022221240 90.00008472 92 > > 51111062.999 51111063 90.00008472 1.022221260 > 90.00011465 92 > > 51111046.001 51111046 90.00011465 1.022220920 90.00014459 > 92 > > 51111028.998 51111029 90.00014459 1.022220580 > > > > The first column is > your data. The second column is a guess about how > > many input cycles were > captured. The third column is the number of > > timebase cycles that have elapsed > since the previous reading, based on > > the first two columns. I hand-tweaked > the numbers in the second column > > until the number in the third column was > within 0.003 of an integer. > > The fact that I was always able to do this tells > me that my guess is > > probably correct, and the small residual (which is a few > parts in > > 1e-10) is due to the counter rounding the results to 10 digits. > The > > 4th column is the result of rounding the previous column to the > > > nearest integer. This is what I believe is the actual number of counts > > the > counter saw. The 5th column is a fresh calculation of frequency, > > based on the > integer number of input cycles in column 2 and the > > integer number of timebase > cycles in column 4. When the result is > > rounded to 10 digits, you can see it > matches the 10 digits that the > > counter provided back in column 1. > > > > > > > Oddly, the counter never captured 91 input cycles. If the input > > frequency was > a little higher than 90 Hz, it always measured at 92 > > cycles, even though 91 > cycles was well more than 1 s since the > > previous reading. I guess the > microprocessor running the counter only > > checks periodically (e.g. every 20 > ms) to see if the gate time has > > elapsed, and then latches the counts on the > next active edge of the > > input signal. > > > > So, I claim that with this small > sample, at least, we recovered the > > exact number of 20 ns periods between > samples, and the number of > > integer input cycles as well. Also notice the 6th > column. This is the > > actual sample interval, based on the number of elapsed > timebase > > counts. Note that the sample period is **not** exactly 1 second, > nor > > is it even close to a constant value, since some measurements are of > > > 90 cycles while others are of 92 cycles. Does your ADEV calculation > > algorithm > take into account the variable spacing of the input samples > > in time? If it > assumes they are regularly spaced (i.e. every 90 > > cycles) it may get confused > by this variable-spacing data. > > > > Now here is almost the same process applied > to your period data: > > > > Reading Input Count TB Count Rounded Period Interval > 0.01111107736 91 > > 50555401.988 50555402 0.01111107736 1.011108040 > 0.01111110130 92 > > 51111065.980 51111066 0.01111110130 1.022221320 > 0.01111110769 91 > > 50555539.990 50555540 0.01111110769 1.011110800 > 0.01111110435 92 > > 51111080.010 51111080 0.01111110435 1.022221600 > 0.01111110593 91 > > 50555531.982 50555532 0.01111110593 1.011110640 > 0.01111110022 90 > > 49999950.990 49999951 0.01111110022 0.999999020 > 0.01111114000 90 > > 50000130.000 50000130 0.01111114000 1.000002600 > 0.01111110000 90 > > 49999950.000 49999950 0.01111110000 0.999999000 > 0.01111110370 92 > > 51111077.020 51111077 0.01111110370 1.022221540 > > > > Again, > column 2 was hand-adjusted for each row to keep the third > > column close to an > integer. The residual errors here are larger, since > > the maximum rounding > error of 0.5 in the last place is a larger change > > relative to a 10-digit > value of 11111111 than it is to a value of > > 90000000, but all are still within > 0.02 of being an integer. This > > time, the counter grabbed measurements after > 90, 91, or 92 cycles. > > Again, after rounding the timebase count to an integer > and calculating > > a 10-digit period for display, the result always matched what > the > > counter output. Again, I think we know with high probability just how > > > many input and timebase cycles were counted for each measurement. > > > > I > adjusted column 2 by eye, while looking at the results of column 3, > > but that > process could be automated pretty easily (just not in Excel). > > As I tried 90, > 91, and 92 in sequence, there was always just one of > > those which gave a small > residual error. > > > > So I think your TF930 is making measurements and > accurately converting > > them to frequency or period, with a +- 20 ns > uncertainty for each > > measurement. Since it is a time-stamping counter, the > uncertainty in a > > 10 s or 100 s or 1000 s measurement time (assembled by > external > > software) is still only 20 ns. That's great, but to actually get > that > > accuracy over a long measurement time, you will need to determine and > > > add up the actual number of input counts and timebase counts. And you > > will > have to understand that the counter does not make measurements at > > constant or > near-constant intervals (e.g. every 90 cycles of input, > > without exception). > It gives you measurements whenever it gets around > > to measuring them. > > > > > Too bad there doesn't seem to be a way to get it to return the raw > > observed > data (input cycle count, timebase cycle count) instead of > > the frequency or > period derived from them. That would make it trivial > > to string together a > bunch of 1s measurements into arbitrarily long > > gate times. > > > > - > Dave > > > > > > On 17/03/2015 05:57, jpbridge@aol.com wrote: > > > > > > Hi > Dave, > > > > Thank you for your detailed response. > > > > I use the E? command > because it returns results at the gate time > > intervals rather than at the LCD > update rate (as you point out). I > > think that this is working correctly > because I get very different > > file sizes. > > > > The numbers are returned as > strings of 10 digits - here are some for 1 > > second gate: > > > > > > > > > > > 90.00006359e+0Hz > > 90.00007591e+0Hz > > 89.99999640e+0Hz > > 89.99998740e+0Hz > > > 90.00006007e+0Hz > > 89.99996040e+0Hz > > 90.00008648e+0Hz > > 90.00008472e+0Hz > > > 90.00011465e+0Hz > > 90.00014459e+0Hz > > > > I generally use the frequency mode > but I also tried time period and > > found I got the same curve in essence, which > was comforting in a way > > but showed it wasn't rounding in converting to > frequency. > > > > The numbers above, on my calculator at least don't exactly > match > > counts of 20 nanosecs. > > > > Here are some time period results: > > > > > 11.11107736e-3s > > 11.11110130e-3s > > 11.11110769e-3s > > 11.11110435e-3s > > > 11.11110593e-3s > > 11.11110022e-3s > > 11.11114000e-3s > > 11.11110000e-3s > > > 11.11110370e-3s > > > > Again they don't seem to be integer values of 20 nanosec > exactly, > > though quite close. For example > > 11.11107736E-3/20E-9 = > 555,553.868 555,554 x 20E-9 = 11.11108E-3 > > > > But I guess what it returns is > the ratio of counts within the gate. So > > 11.11107736E-3 period will occur 90 > times in a second (as it is > > slightly short) and so I should take the > ratio: > > > > 90 x 11.11107736E-3/20e-9 = 49,999,848.12 > > > > so still not quite > an integer but if I assume the count (of 50MHz > > periods) was 49,999,848 and > calculate one 90 th of it I get: > > > > 49,999,848 x 20E-9/90 = > 1.1111077333333 > > > > Still not exact agreement. I note that .12 is very close > to .125 or > > 1/8 but I don't know if that is significant. It is probable that > it > > rounds the ratio in binary and then converts to decimal to print > out. > > > > I've tried assuming 89 periods and 91 periods but still don't get > > > exact integer ratios. > > > > Anyway, as I get good agreement between period and > frequency > > measurements at 1 sec, I don't think that it is a rounding > issue. > > > > I do think it is a quantization issue down to the +/- 20 > nanosecs/gate > > time but I can't quite work it out. > > > > I'm currently doing a > run at 0.3 secs gate time and I'll see what sort > > of curve that > produces. > > > > Tomorrow I should receive my new Tek counter (I went for the > fca3100 > > in the end as I got a very good discount on an ex demo unit) and > > > that should give something to compare (once I've worked out how to > > program > it). > > > > James > > > > > > > > > > > > > > -----Original Message----- From: Dave > Martindale > > <dave.martindale@gmail.com> To: jpbridge <jpbridge@aol.com>; > > > Discussion of precise time and frequency measurement > > <time-nuts@febo.com> > Sent: Tue, 17 Mar 2015 0:27 Subject: Re: > > [time-nuts] ADEV noise floor vs > counter gate time > > > > > > > > > > How is the counter configured? Are you reading > period or frequency? > > Are you in "E?" (Every Result) mode, or "C?" (Continuous > Result) mode? > > The former should give you continuous but independent > measurements, > > while the latter gives heavily overlapped measurements. (For > example, > > with a 100 second gate time, you get one E output every 100 > seconds, > > which covers a different 100-second period than the previous > > > measurement. In C mode, you get one output every 2 seconds, each of > > which is > an estimate from 100 seconds of measurement, but 98 seconds > > of that data was > also part of the previous output and only 2 seconds > > of new data is > included). > > > > > > > > > > What does the data returned by the counter actually > look like? The > > manual implies that you always get 10 digits worth of result > (not > > including the exponent) regardless of gate time, but are the values > > > rounded for display in 7, 8, or 9 digits at the shorter gate times, or > > are > they a full 10 digits always? Given any particular value of > > frequency or > period you get, you should be able to reverse-calculate > > the number of whole > cycles of the input signal that the counter used > > as a gate time, and the > number of cycles of 50 MHz timebase that were > > counted in that period. Since > the counter doesn't have interpolators, > > both of these values should be > integers, and so the possible output > > values are a small subset of all > possible 10-digit values for the > > shorter gate times. > > > > > > > > For example, > if the difference frequency is exactly 90 Hz, the period > > between two "1 > second" measurements will be exactly 1 second, and the > > counter will record 90 > cycles of input and 5e7 cycles of timebase, > > exactly. In frequency mode, the > output should be 90.0 Hz exactly, and > > in period mode the output should be > 11.11111111 ms. Now suppose that > > the difference frequency is just a hair > slow, enough that 90 cycles of > > input spans 50,000,001 counts of the timebase. > The reported frequency > > should be 89.99999820 Hz and the reported period > should be 11.11111133 > > ms. With a 1 s gate time, no values between those are > possible unless > > the values are being rounded (or there is an error in the > calculation, > > which is always possible). Looked at another way, the > smallest > > possible change in the reported period is one timebase clock (20 > ns) > > divided by the number of input cycles in one gate time (90 for 1 > s). > > > > > > > > > > If the counter is rounding, you may be able to unambiguously > figure > > out what the actual inputs (cycles of input and cycles of timebase) > to > > the calculation were, and use that instead of the rounded value in > > your > calculations. Rounding may round up or down, but if the two > > oscillators are > stable enough the direction can be predominantly "up" > > or "down" for long > periods of time, adding a bias to the actual > > frequency or period you're > measuring. (I don't know what effect this > > bias would have on > ADEV). > > > > > > > > > > - Dave > > > > > > > > > > On Mon, Mar 16, 2015 at 10:15 AM, > James via time-nuts > > <time-nuts@febo.com> wrote: > > > > Hi All, > > > > I'm in > the process of getting a better counter, but at present I'm > > using my TTi > TF930 counter. > > > > For those who don't know it, it is a reciprocal counter > which should > > be continuous, it counts periods in terms of its internal 50MHz > clock > > which I've locked to an external 10MHz reference. > > > > There are 4 > gate times available, 0.3 secs, 1 sec, 10 secs and > > 100 secs. > > > > These > correspond to 7, 8, 9 and 10 digits. > > > > I've been experimenting with using a > single mixer (mini circuits ZAD+) > > along with a 1MHz low pass filter and > appropriate attenuators to > > measure Alan Deviation (using my own > software). > > > > My set up is a 10MHz reference source (MV89A which I've > approximately > > set using a 10kHz GPS signal). > > > > The reference is used as > the external reference for an Agilent 33522A > > arbitrary waveform > generator. > > > > The 33522A generates an 9.999910 MHz (10MHz - 90Hz) sine wave > at > > 300mVpp to the mixer and the mixer is also fed by the 10MHz > > reference > output of the 33522A via an attenuator to get it to > > roughly the same > level. > > > > The second output of the 33522A generates a 10MHz square wave as > a > > reference for the counter (the counter requires quite a high reference > > > signal and the reference out of the 33522A is too low a voltage to be > > used > directly). > > > > I initially ran this with a gate of 1 second and the > LOG10(ADEV) curve > > drops linearly vs LOG10(tau) but then curves back up again. > (I tried > > many variants such as using period rather than frequency and so > on.) > > > > But when I set the gate time to 10 seconds or 100 seconds then I > get > > both lower curves and ones that no longer curve upwards. > > > > The > attached pdf shows the three curves on the same graph. > > > > What puzzles me is > that the counter at longer gates is only averaging > > to get more digits so the > difference must come down to quantization in > > terms of the number of digits > that are passed to the computer over the > > USB/RS232 link. > > > > I find it > rather puzzling. > > > > James > > > > > > > > > > > > > > > _________________________________________________ > > time-nuts mailing list -- > time-nuts@febo.com To unsubscribe, go to > > > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the > > > instructions there. > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > _________________________________________________ > > time-nuts mailing list -- > time-nuts@febo.com To unsubscribe, go to > > > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the > > > instructions > there. > > _______________________________________________ > time-nuts mailing > list -- time-nuts@febo.com > To unsubscribe, go to > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the > instructions there. > > > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there. _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.