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Re: T&T: Propeller efficiency

L
LRZeitlin@aol.com
Wed, Aug 1, 2007 8:05 PM

I read, with interest, the comments on propeller efficiency in recent posts.
Propeller efficiency is one of those ambiguous areas in boating, like
seaworthiness or handling, that is important but difficult to understand.

Basically propeller efficiency is defined as the percent of shaft horsepower
that is used to propel the boat. All one must do to calculate propeller
efficiency is determine the amount of power input to the propeller (fairly easy),
the speed of the boat through the water (very easy) and the thrust of the
propeller at that speed (quite difficult). The amount of slip, per se, is primarily
a function of the design factors that determine efficiency. The effective
horsepower (EHP) is the amount of power necessary to overcome the drag and move
the boat through the water at the required speed. For displacement boats, very
little EHP is necessary to move the boat at S/L ratios below 1. For
non-technophiles, the S/L ratio is the boat speed in knots divided by the square root of
the waterline length in feet. Above a S/L ratio of 1 the power required rises
exponentially. The hull speed of a displacement type boat is generally held to
be at a S/L ratio of 1.34.

Let's take an example. My Willard trawler engine is required to generate
about 13.7 horsepower to move the boat at 6 knots. This is a S/L of 1.15. Power
can be measured exactly with the correct instruments but in my case I just
calculated it by measuring the fuel consumption over a long cruise at a 6 knot
speed. The average fuel consumption was .82 gph. Using the estimate of .06 gph per
horsepower, the developed power came out to 13.66 hp. The gearbox, long
shaft, and several bearings probably reduced the power available at the prop to 13
hp.

Since one horsepower equals 550 ft. lbs. per second, a 100 % efficient prop
would develop 7150 ft. lbs./sec. of force. Since the boat, traveling at 6
knots, is moving at 10.1 feet/second, the prop should be delivering about 708 lbs.
of thrust.

Now here is where the efficiency calculation gets harder. I must know the
actual drag of the boat to determine the amount of thrust necessary to move it at
6 knots. This can only be determined by towing the boat or tank testing. I
could get a rough estimate by measuring the bollard pull but that would only
tell me the amount of thrust developed at zero velocity, not at speed. In the few
instances I have tried to drag an anchor or tow another stranded boat, I am
sure that the prop did not develop 708 lbs. of thrust. It probably developed
about 300 lbs. of thrust at the same engine rpm that I use for cruising.

Now let us assume that the 300 lb. thrust figure is correct. The equation for
efficiency is:

Efficiency = (power output/power input ) x 100

The power output of the prop is 10.1 ft/sec x 300 lbs. thrust. This works out
to 3030 ft. lbs./sec. Since the power input to the prop is equivalent to 7150
ft. lbs./sec., the prop is working at only 42.4% efficiency. This is in the
range of efficiency of most trawler props which rarely exceed efficiencies of
greater than 50%.

Now let's arrive at an estimate of prop efficiency another way. Francis
Kinney, in "Skene's Elements of Yacht Design," the holy writ of boat designers,
provides a chart showing the resistance of displacement type hulls as a function
of speed. At a S/L ratio of 1.15 my Willard has a drag of 35 lbs. per long ton
(2240 lbs.) of displacement. My boat has a total displacement of 7.14 long
tons hence the total drag is about 250 lbs at 6 knots. The formula for effective
horsepower is:

EHP = resistance x speed x .003

For my boat this works out to:

EHP = 250 x 6 x .003 = 4.5

Thus it takes only 4.5 hp directly applied to the boat to move it at 6 knots.

Dividing the 4.5 EHP by the 13 hp applied to the prop gives me a propeller
efficiency of only 35%. This is not too far from the previously calculated
efficiency of 42%. This is low but in the ballpark for most recreational trawlers.
In fact in years of consulting on small boat designs I have rarely seen a
recreational trawler with a propeller efficiency of as much as 50%.

Greater efficiencies can be obtained by increasing the thrust of the prop at
a given power input. Thrust is determined by the mass and velocity of the
water accelerated backward by the prop. You can move a large amount of water
backward at a slow speed or a small amount at a high speed (i.e. firehose). For
propelling a boat forward, it is most effective to move a large amount of water
backward at a speed slightly higher than the boat's forward speed. The amount
of water moved is determined by the prop blade diameter and the prop pitch. The
blade area should be sufficient to avoid cavitation at maximum prop rpm.
Generally, the fewer blades the better, given sufficient blade area, because each
blade is moving in clearer water. You can move the same amount of water by a
smaller prop turning at a faster speed but higher rpm means greater friction
losses and generally lower efficiency.

So we find that the most efficient props for displacement and semi planing
boats are large diameter, low rpm, relatively a high pitch matched to boat
speed, with just sufficient blade area to avoid cavitation. Using this approach, it
is theoretically possible to get prop efficiencies approaching 75% but there
may be practical limitations of clearance, draft, and unsuitability for
certain hull designs.

There will be no exam.

Larry Z


Get a sneak peek of the all-new
AOL at http://discover.aol.com/memed/aolcom30tour

I read, with interest, the comments on propeller efficiency in recent posts. Propeller efficiency is one of those ambiguous areas in boating, like seaworthiness or handling, that is important but difficult to understand. Basically propeller efficiency is defined as the percent of shaft horsepower that is used to propel the boat. All one must do to calculate propeller efficiency is determine the amount of power input to the propeller (fairly easy), the speed of the boat through the water (very easy) and the thrust of the propeller at that speed (quite difficult). The amount of slip, per se, is primarily a function of the design factors that determine efficiency. The effective horsepower (EHP) is the amount of power necessary to overcome the drag and move the boat through the water at the required speed. For displacement boats, very little EHP is necessary to move the boat at S/L ratios below 1. For non-technophiles, the S/L ratio is the boat speed in knots divided by the square root of the waterline length in feet. Above a S/L ratio of 1 the power required rises exponentially. The hull speed of a displacement type boat is generally held to be at a S/L ratio of 1.34. Let's take an example. My Willard trawler engine is required to generate about 13.7 horsepower to move the boat at 6 knots. This is a S/L of 1.15. Power can be measured exactly with the correct instruments but in my case I just calculated it by measuring the fuel consumption over a long cruise at a 6 knot speed. The average fuel consumption was .82 gph. Using the estimate of .06 gph per horsepower, the developed power came out to 13.66 hp. The gearbox, long shaft, and several bearings probably reduced the power available at the prop to 13 hp. Since one horsepower equals 550 ft. lbs. per second, a 100 % efficient prop would develop 7150 ft. lbs./sec. of force. Since the boat, traveling at 6 knots, is moving at 10.1 feet/second, the prop should be delivering about 708 lbs. of thrust. Now here is where the efficiency calculation gets harder. I must know the actual drag of the boat to determine the amount of thrust necessary to move it at 6 knots. This can only be determined by towing the boat or tank testing. I could get a rough estimate by measuring the bollard pull but that would only tell me the amount of thrust developed at zero velocity, not at speed. In the few instances I have tried to drag an anchor or tow another stranded boat, I am sure that the prop did not develop 708 lbs. of thrust. It probably developed about 300 lbs. of thrust at the same engine rpm that I use for cruising. Now let us assume that the 300 lb. thrust figure is correct. The equation for efficiency is: Efficiency = (power output/power input ) x 100 The power output of the prop is 10.1 ft/sec x 300 lbs. thrust. This works out to 3030 ft. lbs./sec. Since the power input to the prop is equivalent to 7150 ft. lbs./sec., the prop is working at only 42.4% efficiency. This is in the range of efficiency of most trawler props which rarely exceed efficiencies of greater than 50%. Now let's arrive at an estimate of prop efficiency another way. Francis Kinney, in "Skene's Elements of Yacht Design," the holy writ of boat designers, provides a chart showing the resistance of displacement type hulls as a function of speed. At a S/L ratio of 1.15 my Willard has a drag of 35 lbs. per long ton (2240 lbs.) of displacement. My boat has a total displacement of 7.14 long tons hence the total drag is about 250 lbs at 6 knots. The formula for effective horsepower is: EHP = resistance x speed x .003 For my boat this works out to: EHP = 250 x 6 x .003 = 4.5 Thus it takes only 4.5 hp directly applied to the boat to move it at 6 knots. Dividing the 4.5 EHP by the 13 hp applied to the prop gives me a propeller efficiency of only 35%. This is not too far from the previously calculated efficiency of 42%. This is low but in the ballpark for most recreational trawlers. In fact in years of consulting on small boat designs I have rarely seen a recreational trawler with a propeller efficiency of as much as 50%. Greater efficiencies can be obtained by increasing the thrust of the prop at a given power input. Thrust is determined by the mass and velocity of the water accelerated backward by the prop. You can move a large amount of water backward at a slow speed or a small amount at a high speed (i.e. firehose). For propelling a boat forward, it is most effective to move a large amount of water backward at a speed slightly higher than the boat's forward speed. The amount of water moved is determined by the prop blade diameter and the prop pitch. The blade area should be sufficient to avoid cavitation at maximum prop rpm. Generally, the fewer blades the better, given sufficient blade area, because each blade is moving in clearer water. You can move the same amount of water by a smaller prop turning at a faster speed but higher rpm means greater friction losses and generally lower efficiency. So we find that the most efficient props for displacement and semi planing boats are large diameter, low rpm, relatively a high pitch matched to boat speed, with just sufficient blade area to avoid cavitation. Using this approach, it is theoretically possible to get prop efficiencies approaching 75% but there may be practical limitations of clearance, draft, and unsuitability for certain hull designs. There will be no exam. Larry Z ************************************** Get a sneak peek of the all-new AOL at http://discover.aol.com/memed/aolcom30tour
JB
John Baker
Thu, Aug 2, 2007 10:17 PM

Larry,

   The question was still not answered.....3 blades or four???

   

Pinpoint customers who are looking for what you sell.

Larry, The question was still not answered.....3 blades or four??? --------------------------------- Pinpoint customers who are looking for what you sell.