In Part 1 we looked at general considerations of anchopring. Now let us calculate the strain on the rode and the forces on the anchor. We will start with an all chain rode, then progress to elastic chain and nylon rodes. Don't be put off by the equations that follow. The math in the first part of the essay is used to justify the conclusions reached in the latter part. There will be no exam. First, we must determine the horizontal force on the boat attempting to pull the anchor loose. WIND DRAG in lbs = .00339 * Cd * V * V * A where: Cd = drag coefficient, a dimensionless number determined by wind tunnel tests. For most pleasure boats this number is approximately .80. V = wind speed in Knots. A = total frontal area in sq. feet. This includes hull, deck house, mast and rigging. Thus for an 80 sq. ft. area pleasure boat in a 60 kt. wind, the total wind drag = 781 lbs. This frontal area approximates that of most pleasure boats in the 30 to 40 foot range. Current drag is equal to the thrust necessary to move the boat ahead in still water at the same speed as the current. It can be found from propulsion data by this equation: CURRENT DRAG in lbs. = 325.5(P x RPM - 1216 x V) / (V x P x RPM) where: P = propeller pitch in inches, RPM = propeller revolutions per minute, V = velocity in knots, H = engine HP delivered at the desired speed. If you know this, great. If not, it can be estimated by Keith's formula which comes next. Thus a 40 ft. yacht, estimated to require 20 HP to go 5 kt. with a prop pitch of 8" at 1000 shaft RPM would have a drag of 312.5 lbs. in a 5 kt. current. Keith's formula for (roughly) estimating required HP is: HP = Displacement in lbs. x (V / 11.8 x LWL^.5)^3 Wave action loads are difficult to estimate since they depend both on the length of the boat and the period of the waves. Basically wave action imposes severe loads when the boat is pitching in resonance with the waves. Fortunately in strong winds wave lengths quickly grow to the point where resonance is unlikely for modestly sized pleasure boats. The horizontal anchoring load is determined by the sum of wind drag and current drag, with occasional shock loads imposed by wave action. I usually increase my estimate of the horizontal load by 20% to provide a safety margin for the unpredictability of wave and other transient loads. We can calculate the horizontal anchor rode requirements using the following equations: RODE TENSION (in lbs.) FOR CHAIN T = Th + (w * d) where: T = maximum tension in line in lbs. Th = horizontal load in lbs. (i.e. the sum of wind and current and wave drags) w = underwater weight of rode in lbs/ft. d = depth of water in feet (including max. tides and wave heights) Next we must determine the vertical load. This is a major consideration for chain rodes where the weight of the chain impedes the ability of the bow to rise in waves. VERTICAL LOAD (in lbs.) FOR CHAIN Tv = sq. rt. of ((T * T) - (Th * Th)) where: Tv = vertical load in lbs. LENGTH OF RODE (in ft.) FOR CHAIN Length = Tv/w Let's see what it takes to anchor our hypothetical 80 sq. ft. area boat in a 60kt. wind. The underwater weight of steel chain is .87 of its weight in air. If we assume a horizontal load of 1000 lbs, 30 ft. of water and 5/16" chain (which weighs 1.0 lbs./ft. underwater) we find that: Horizontal load = T = 1000 + (30 * 1.0) = 1030 lbs. Vertical load = Tv = 247 lbs. Rode length = 247 ft. Scope = Length to depth ratio = 8.23 Now if we increase the chain diameter to 1/2" (underwater weight is 2.57 lbs./ft.), we get: Horizontal load = T = 1000 + (30 * 2.57) = 1077 lbs. Vertical load = Tv = 400 lbs. Rode length = 156 ft. Scope = Length/d = 5.2 Increasing the chain diameter lets us cut the length of the rode by 91 ft., about a third, however it almost doubles the vertical weight on the bow and would materially decrease its ability to lift over waves. A effect similar to using heavier chain can be achieved by fixing a weight roughly equivalent to the difference in weights of the heavier over the lighter chain near the midpoint of the rode. In both cases the chain is far stronger than necessary to handle the load, the scope reduction attributed to the larger chain comes simply from its increased weight. The anchor, of course, has to be capable of holding the horizontal load. Anchor makers generally give very optimistic figures for the holding power of their products. For example, if the Danforth catalog is to be believed, a 5H anchor, just about key chain sized, holds 2700 lbs in hard sand. A muddy bottom would require a 20H to 35H anchor. My own approach is to use the biggest anchor my wife can lift and the longest nylon rode that I can let out in a given anchorage. There are several basic problems when using a nylon rode. The first is to assure adequate elasticity. New, three strand standard laid nylon rope can stretch up to 50% before breaking. The stretch at lower tensions is almost directly proportional to the strain. An elastic nylon rode should be designed to stretch about 15% to 20% between maximum and no load conditions. If the rope is too thick, it will not stretch sufficiently and you have the equivalent of a chain rode without the catenary effect of chain. The best way of determining the optimum diameter for the nylon rope is to calculate the maximum expected tension on the line, double it, then consult a table of nylon rope strengths to determine the required diameter. The second main problem of nylon rodes is abrasion. Most nylon rodes fail because they rub against rough surfaces and chafe through. One solution is to use chafe protection at vulnerable points. The elasticity of nylon works against it in extreme conditions. The stretching and relaxation of dry nylon can cause enough internal friction to actually melt the fibers and weaken the rope. This doesn't happen if the rope is kept wet. The chafe protection must be porous enough to let water penetrate in storm conditions. An alternative plan is to use a dacron rode. Dacron is highly resistant to chafe. But while an all dacron rode will not wear through, it has very little elasticity. A composite rode was proposed by MIT researchers. A nylon rode of the appropriate strength and length was spliced to a dacron pennant which was attached to the cleats of the boat. The splice, consisting of interlocking eye splices at the junction, was under water. Tests to destruction showed that the rode never failed at the splice. Thus our hypothetical pleasure boat, anchored in a 60 kt. wind, with an anchor rode tension of 1030 lbs. would require a nylon anchor rode .424 inches in diameter. In this case I would use a 1/2" rope. Most modern lightweight anchors are designed to work with the pull on the shank being no more than 8 degrees above the horizontal. This includes Danforths, Fortresses, Ploughs, Deltas, and their variants. The sine of 8 degrees = .139. To achieve the required angle with an unweighted line, the line must be (DEPTH/.139) long or about 7.2 times the depth of the water. This is where the famous 7:1 scope requirement comes from. Any weight placed near the shank lowers this requirement. So a length of chain placed next to the shank of a lightweight anchor satisfies two requirements at once. It lessens the slope of the line and protects the vulnerable nylon from abrasion. Calculations for the optimum length of chain on a combined nylon chain rode are complex. However William van Dorn in "Oceanography and Seamanship"; Dodd, Mead (1974), presents a graph based on calculations for anchoring oceanographic vessels in storm conditions. It suggests that the optimum chain/nylon combination for anchoring vessels < 50ft. in 30 ft. of water under storm conditions is a 20% chain, 80% nylon rode with an overall scope of 6:1. Assuming that the boat's bow chock is 6 feet above the water and that the waves are 4 feet (8 feet peak to trough) this works out to a 240 foot total rode comprised of 48 feet of chain and 192 feet of nylon. Clearly these are extreme conditions. The length of chain required approximates one boat length and a good working rule for a combined rode is a boat length of chain plus whatever nylon is required to give a 6:1 scope. In shallower water, the scope should be increased, within swing limitations, to 7:1 to permit the bow to lift more easily to the choppy waves near the shore. Although a 60 kt. wind is well into gale force levels, hurricane winds are much stronger. If you want to cope with 120 kt. winds, anchor and rode will have to be four times stronger and it is unlikely that a single anchor of a size usually carried aboard a trawler will be sufficient. Multiple anchors and rodes will be required in these conditions. And for God's sake get off the boat and spend the next couple of days ashore. Trust the Force and your insurance company. In summary, at a fixed anchoring depth, the longer the rode, the less chain required. The shortest rodes are achieved with all chain, the heavier the better, but the penalty is increased weight and handling difficulty, and the slightly increased possibility of catastrophic failure if the chain stretches taut. Don't drag! Larry Zeitlin ************************************** See what's free at http://www.aol.com. ************************************** See what's free at http://www.aol.com.