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GPS Time to Year?

BC
Brooke Clarke
Thu, Jan 22, 2009 7:20 PM

Hi:

It's my understanding that the slowest time data from GPS is the 10 bit week
number.
How does a GPS receiver come up with the current Year?

--
Have Fun,

Brooke Clarke
http://www.prc68.com

Hi: It's my understanding that the slowest time data from GPS is the 10 bit week number. How does a GPS receiver come up with the current Year? -- Have Fun, Brooke Clarke http://www.prc68.com
TV
Tom Van Baak
Thu, Jan 22, 2009 9:06 PM

Hi:

It's my understanding that the slowest time data from GPS is the 10 bit week
number.
How does a GPS receiver come up with the current Year?

--
Have Fun,

Brooke Clarke

Hi Brooke,

Good question. You are correct that this 10-bit week number
wraps once every 2^10=1024 weeks which is once about every
20 years. It's not the slowest GPS data, see below *.

Other GPS fields also wrap (more quickly) in a binary way.
Most wrist watches, for that matter, wrap 60 seconds, or 60
minutes, or 12 hours.

Note:
GPS week 0 started MJD 44244 = 1980-01-06
GPS week 0 (1024) started MJD 51412 = 1999-08-22
GPS week 0 (2048) starts MJD 58580 = 2019-04-07
GPS week 0 (3072) starts MJD 65748 = 2038-11-21

The ways GPS receivers come up with the current year are:

  1. Since time moves forward only, the real year can't less than
    what the year was yesterday. So when a GPS receiver on, say,
    Sunday morning April 4, 2019 sees that the GPS week is now 0
    while last night the week was 1023, the GPS receiver can be very
    sure that the year is still 2019 and not 1980 or 1999 or 2019. As
    long as a GPS receiver has NVRAM you're all set.

  2. The real year can't be less than the year the GPS receiver was
    manufactured. If the firmware sees GPS week 491, is has the
    option to decide if that week means 0+491 (June 1989) or 1024+491
    (January 2009) or 2048+491 (September 2028). With a +/- 10 year
    margin the GPS receiver can pick the correct one.

On the other hand, those of us with boat anchor GPS receivers from
August 1999 know that firmware isn't always perfect.'

  1. The real year can be obtained from external sources. Many GPS
    receivers are now embedded into cell phone or internet-enabled
    devices so obtaining a hint at the current date is easy. One may
    even know the date&time well before the first GPS signal lock.

  2. The real year can't have fewer leap seconds than the previous
    year. So if you see that the GPS week number is 0 and the UTC
    vs. TAI leap second count is around 20 seconds you know it's
    GPS week 0 and year 1980. If the leap second count is closer to
    32 seconds you know it's GPS week 0(1024) and so year 1999.
    If the count is closer to, say, 44 seconds, then you can be safe
    that it's GPS week 0(2048), or year 2019. Not perfect, but it will
    work fine for our lifetimes and more.

/tvb

*) The 8-bit leap second number is slower, wrapping once every
couple of hundred years. Note also that the new GPS data format
allows for wider bit fields for this and other parameters. See also:
http://leapsecond.com/notes/gpswnro.htm

> Hi: > > It's my understanding that the slowest time data from GPS is the 10 bit week > number. > How does a GPS receiver come up with the current Year? > > -- > Have Fun, > > Brooke Clarke Hi Brooke, Good question. You are correct that this 10-bit week number wraps once every 2^10=1024 weeks which is once about every 20 years. It's not the slowest GPS data, see below *. Other GPS fields also wrap (more quickly) in a binary way. Most wrist watches, for that matter, wrap 60 seconds, or 60 minutes, or 12 hours. Note: GPS week 0 started MJD 44244 = 1980-01-06 GPS week 0 (1024) started MJD 51412 = 1999-08-22 GPS week 0 (2048) starts MJD 58580 = 2019-04-07 GPS week 0 (3072) starts MJD 65748 = 2038-11-21 The ways GPS receivers come up with the current year are: 1) Since time moves forward only, the real year can't less than what the year was yesterday. So when a GPS receiver on, say, Sunday morning April 4, 2019 sees that the GPS week is now 0 while last night the week was 1023, the GPS receiver can be very sure that the year is still 2019 and not 1980 or 1999 or 2019. As long as a GPS receiver has NVRAM you're all set. 2) The real year can't be less than the year the GPS receiver was manufactured. If the firmware sees GPS week 491, is has the option to decide if that week means 0+491 (June 1989) or 1024+491 (January 2009) or 2048+491 (September 2028). With a +/- 10 year margin the GPS receiver can pick the correct one. On the other hand, those of us with boat anchor GPS receivers from August 1999 know that firmware isn't always perfect.' 3) The real year can be obtained from external sources. Many GPS receivers are now embedded into cell phone or internet-enabled devices so obtaining a hint at the current date is easy. One may even know the date&time well before the first GPS signal lock. 4) The real year can't have fewer leap seconds than the previous year. So if you see that the GPS week number is 0 and the UTC vs. TAI leap second count is around 20 seconds you know it's GPS week 0 and year 1980. If the leap second count is closer to 32 seconds you know it's GPS week 0(1024) and so year 1999. If the count is closer to, say, 44 seconds, then you can be safe that it's GPS week 0(2048), or year 2019. Not perfect, but it will work fine for our lifetimes and more. /tvb *) The 8-bit leap second number is slower, wrapping once every couple of hundred years. Note also that the new GPS data format allows for wider bit fields for this and other parameters. See also: http://leapsecond.com/notes/gpswnro.htm
MW
M. Warner Losh
Thu, Jan 22, 2009 9:37 PM

In message: C3CD6F936E3E4EE99880B074162AB49C@pc52
"Tom Van Baak" tvb@LeapSecond.com writes:
: > Hi:
: >
: > It's my understanding that the slowest time data from GPS is the 10 bit week
: > number.
: > How does a GPS receiver come up with the current Year?
: >
: > --
: > Have Fun,
: >
: > Brooke Clarke
:
: Hi Brooke,
:
: Good question. You are correct that this 10-bit week number
: wraps once every 2^10=1024 weeks which is once about every
: 20 years. It's not the slowest GPS data, see below *.
:
: Other GPS fields also wrap (more quickly) in a binary way.
: Most wrist watches, for that matter, wrap 60 seconds, or 60
: minutes, or 12 hours.
:
: Note:
: GPS week 0 started MJD 44244 = 1980-01-06
: GPS week 0 (1024) started MJD 51412 = 1999-08-22
: GPS week 0 (2048) starts MJD 58580 = 2019-04-07
: GPS week 0 (3072) starts MJD 65748 = 2038-11-21
:
: The ways GPS receivers come up with the current year are:
:
: 1) Since time moves forward only, the real year can't less than
: what the year was yesterday. So when a GPS receiver on, say,
: Sunday morning April 4, 2019 sees that the GPS week is now 0
: while last night the week was 1023, the GPS receiver can be very
: sure that the year is still 2019 and not 1980 or 1999 or 2019. As
: long as a GPS receiver has NVRAM you're all set.

That works.  Even in the coldest of spares will have been on sometime
in the last 20 years, which is all that's needed to make this work...

: 2) The real year can't be less than the year the GPS receiver was
: manufactured. If the firmware sees GPS week 491, is has the
: option to decide if that week means 0+491 (June 1989) or 1024+491
: (January 2009) or 2048+491 (September 2028). With a +/- 10 year
: margin the GPS receiver can pick the correct one.
:
: On the other hand, those of us with boat anchor GPS receivers from
: August 1999 know that firmware isn't always perfect.'

:)

: 3) The real year can be obtained from external sources. Many GPS
: receivers are now embedded into cell phone or internet-enabled
: devices so obtaining a hint at the current date is easy. One may
: even know the date&time well before the first GPS signal lock.

That's cheating...

: 4) The real year can't have fewer leap seconds than the previous
: year. So if you see that the GPS week number is 0 and the UTC
: vs. TAI leap second count is around 20 seconds you know it's
: GPS week 0 and year 1980. If the leap second count is closer to
: 32 seconds you know it's GPS week 0(1024) and so year 1999.
: If the count is closer to, say, 44 seconds, then you can be safe
: that it's GPS week 0(2048), or year 2019. Not perfect, but it will
: work fine for our lifetimes and more.

Yes.  Assuming there's no huge acceleration of the earth...  Possible,
but very unlikely...

And assuming that leap seconds continue...  If they stop, it will be
hard to know...  But if they stop, I can imagine that we could use
DUT1 that would have to be published...

: *) The 8-bit leap second number is slower, wrapping once every
: couple of hundred years. Note also that the new GPS data format
: allows for wider bit fields for this and other parameters. See also:
: http://leapsecond.com/notes/gpswnro.htm

True...

Warner

In message: <C3CD6F936E3E4EE99880B074162AB49C@pc52> "Tom Van Baak" <tvb@LeapSecond.com> writes: : > Hi: : > : > It's my understanding that the slowest time data from GPS is the 10 bit week : > number. : > How does a GPS receiver come up with the current Year? : > : > -- : > Have Fun, : > : > Brooke Clarke : : Hi Brooke, : : Good question. You are correct that this 10-bit week number : wraps once every 2^10=1024 weeks which is once about every : 20 years. It's not the slowest GPS data, see below *. : : Other GPS fields also wrap (more quickly) in a binary way. : Most wrist watches, for that matter, wrap 60 seconds, or 60 : minutes, or 12 hours. : : Note: : GPS week 0 started MJD 44244 = 1980-01-06 : GPS week 0 (1024) started MJD 51412 = 1999-08-22 : GPS week 0 (2048) starts MJD 58580 = 2019-04-07 : GPS week 0 (3072) starts MJD 65748 = 2038-11-21 : : The ways GPS receivers come up with the current year are: : : 1) Since time moves forward only, the real year can't less than : what the year was yesterday. So when a GPS receiver on, say, : Sunday morning April 4, 2019 sees that the GPS week is now 0 : while last night the week was 1023, the GPS receiver can be very : sure that the year is still 2019 and not 1980 or 1999 or 2019. As : long as a GPS receiver has NVRAM you're all set. That works. Even in the coldest of spares will have been on sometime in the last 20 years, which is all that's needed to make this work... : 2) The real year can't be less than the year the GPS receiver was : manufactured. If the firmware sees GPS week 491, is has the : option to decide if that week means 0+491 (June 1989) or 1024+491 : (January 2009) or 2048+491 (September 2028). With a +/- 10 year : margin the GPS receiver can pick the correct one. : : On the other hand, those of us with boat anchor GPS receivers from : August 1999 know that firmware isn't always perfect.' :) : 3) The real year can be obtained from external sources. Many GPS : receivers are now embedded into cell phone or internet-enabled : devices so obtaining a hint at the current date is easy. One may : even know the date&time well before the first GPS signal lock. That's cheating... : 4) The real year can't have fewer leap seconds than the previous : year. So if you see that the GPS week number is 0 and the UTC : vs. TAI leap second count is around 20 seconds you know it's : GPS week 0 and year 1980. If the leap second count is closer to : 32 seconds you know it's GPS week 0(1024) and so year 1999. : If the count is closer to, say, 44 seconds, then you can be safe : that it's GPS week 0(2048), or year 2019. Not perfect, but it will : work fine for our lifetimes and more. Yes. Assuming there's no huge acceleration of the earth... Possible, but very unlikely... And assuming that leap seconds continue... If they stop, it will be hard to know... But if they stop, I can imagine that we could use DUT1 that would have to be published... : *) The 8-bit leap second number is slower, wrapping once every : couple of hundred years. Note also that the new GPS data format : allows for wider bit fields for this and other parameters. See also: : http://leapsecond.com/notes/gpswnro.htm True... Warner
MD
Magnus Danielson
Thu, Jan 22, 2009 11:58 PM

Tom Van Baak skrev:

Hi:

It's my understanding that the slowest time data from GPS is the 10 bit week
number.
How does a GPS receiver come up with the current Year?

--
Have Fun,

Brooke Clarke

Hi Brooke,

Good question. You are correct that this 10-bit week number
wraps once every 2^10=1024 weeks which is once about every
20 years. It's not the slowest GPS data, see below *.

Other GPS fields also wrap (more quickly) in a binary way.
Most wrist watches, for that matter, wrap 60 seconds, or 60
minutes, or 12 hours.

Note:
GPS week 0 started MJD 44244 = 1980-01-06
GPS week 0 (1024) started MJD 51412 = 1999-08-22
GPS week 0 (2048) starts MJD 58580 = 2019-04-07
GPS week 0 (3072) starts MJD 65748 = 2038-11-21

The ways GPS receivers come up with the current year are:

  1. Since time moves forward only, the real year can't less than
    what the year was yesterday. So when a GPS receiver on, say,
    Sunday morning April 4, 2019 sees that the GPS week is now 0
    while last night the week was 1023, the GPS receiver can be very
    sure that the year is still 2019 and not 1980 or 1999 or 2019. As
    long as a GPS receiver has NVRAM you're all set.

  2. The real year can't be less than the year the GPS receiver was
    manufactured. If the firmware sees GPS week 491, is has the
    option to decide if that week means 0+491 (June 1989) or 1024+491
    (January 2009) or 2048+491 (September 2028). With a +/- 10 year
    margin the GPS receiver can pick the correct one.

On the other hand, those of us with boat anchor GPS receivers from
August 1999 know that firmware isn't always perfect.'

  1. The real year can be obtained from external sources. Many GPS
    receivers are now embedded into cell phone or internet-enabled
    devices so obtaining a hint at the current date is easy. One may
    even know the date&time well before the first GPS signal lock.

  2. The real year can't have fewer leap seconds than the previous
    year. So if you see that the GPS week number is 0 and the UTC
    vs. TAI leap second count is around 20 seconds you know it's
    GPS week 0 and year 1980. If the leap second count is closer to
    32 seconds you know it's GPS week 0(1024) and so year 1999.
    If the count is closer to, say, 44 seconds, then you can be safe
    that it's GPS week 0(2048), or year 2019. Not perfect, but it will
    work fine for our lifetimes and more.

You could use leap second counter as a rought estimate to get the right
1024 week interval. Naturally, if leap seconds is no longer inserted
that would break that algorithm. I wonder if this hint have been used by
any receivers.. :)

You can also use a CMOS backed clock, which many receivers have or there
is an external option for a backup battery. That hint is usually valid
enought. Also, the CMOS clock can be maintained when running. Storing
last seen leap second and week number along with date at time of storage
in the CMOS backup memory could also be usefull.

Cheers,
Magnus

Tom Van Baak skrev: >> Hi: >> >> It's my understanding that the slowest time data from GPS is the 10 bit week >> number. >> How does a GPS receiver come up with the current Year? >> >> -- >> Have Fun, >> >> Brooke Clarke > > Hi Brooke, > > Good question. You are correct that this 10-bit week number > wraps once every 2^10=1024 weeks which is once about every > 20 years. It's not the slowest GPS data, see below *. > > Other GPS fields also wrap (more quickly) in a binary way. > Most wrist watches, for that matter, wrap 60 seconds, or 60 > minutes, or 12 hours. > > Note: > GPS week 0 started MJD 44244 = 1980-01-06 > GPS week 0 (1024) started MJD 51412 = 1999-08-22 > GPS week 0 (2048) starts MJD 58580 = 2019-04-07 > GPS week 0 (3072) starts MJD 65748 = 2038-11-21 > > The ways GPS receivers come up with the current year are: > > 1) Since time moves forward only, the real year can't less than > what the year was yesterday. So when a GPS receiver on, say, > Sunday morning April 4, 2019 sees that the GPS week is now 0 > while last night the week was 1023, the GPS receiver can be very > sure that the year is still 2019 and not 1980 or 1999 or 2019. As > long as a GPS receiver has NVRAM you're all set. > > 2) The real year can't be less than the year the GPS receiver was > manufactured. If the firmware sees GPS week 491, is has the > option to decide if that week means 0+491 (June 1989) or 1024+491 > (January 2009) or 2048+491 (September 2028). With a +/- 10 year > margin the GPS receiver can pick the correct one. > > On the other hand, those of us with boat anchor GPS receivers from > August 1999 know that firmware isn't always perfect.' > > 3) The real year can be obtained from external sources. Many GPS > receivers are now embedded into cell phone or internet-enabled > devices so obtaining a hint at the current date is easy. One may > even know the date&time well before the first GPS signal lock. > > 4) The real year can't have fewer leap seconds than the previous > year. So if you see that the GPS week number is 0 and the UTC > vs. TAI leap second count is around 20 seconds you know it's > GPS week 0 and year 1980. If the leap second count is closer to > 32 seconds you know it's GPS week 0(1024) and so year 1999. > If the count is closer to, say, 44 seconds, then you can be safe > that it's GPS week 0(2048), or year 2019. Not perfect, but it will > work fine for our lifetimes and more. You could use leap second counter as a rought estimate to get the right 1024 week interval. Naturally, if leap seconds is no longer inserted that would break that algorithm. I wonder if this hint have been used by any receivers.. :) You can also use a CMOS backed clock, which many receivers have or there is an external option for a backup battery. That hint is usually valid enought. Also, the CMOS clock can be maintained when running. Storing last seen leap second and week number along with date at time of storage in the CMOS backup memory could also be usefull. Cheers, Magnus